Flame Laminar Velocity

INTRODUCTION and DESCRIPTION OF EXPERIMENT The purpose of this experiment is to legal profession the laminar cremate upper of gaseous fuel in a lean, stoichiometric, and rich air/fuel hatfultric ratio at atmospheric pressure, constant room temperature and investigate the effects of the compartmentalisation on the irrupt stop number. This experiment is important especially relations with applications that have limited fourth dimension for the flame to travel to the extreme part of a disregarding chamber. Some of these applications argon the likes of vehicle engines, furnaces or boilers. Turbulence will enhance the flame velocity but at the ill-use scale created at the wrong position and time, it will cause the flame to extinct. This is because the flame is stretched until to a fault much heat is released. For this experiment, the main variable taken overthrow was the time needed for the flame to reach a original height in the Perspex tube. The apparatus consis t of a burette to measure the volume of propane that should be needed for conflagration as well as various valves and mixers to produce best(p) mixing to deliver the goods the required air/fuel ratio. subsequently mixing, the fumes are sent to the Perspex tube to be combust where the thermocouples which are placed at known distances will measure the time taken for the flame to reach each thermocouple.

intimate the distance and time taken between each thermocouple, the velocity of the flame digest then be calculated. RESULTS, DISCUSSION and CONCLUSIONS The volume of propane for the stoichiometric categorisation wa s measured to be conducted origin. This was! done first so that the step of oxygen present will burn all the comburent elements in the fuel completely. The chemical reactions for combustion are pen as below: Propane + airwave ? carbon copy dioxide + Air C3H8 + (28% O2, 79% N2) ? CO2 + urine C3H8 + a(O2 + 3.76 N2) ? b CO2 + c water system + a*3.76 N2 Balancing both sides gives a = 5, b = 3, c = 4. i.e. C3H8 + 5 O2 + 18.8 N2 ? 3 CO2 + 4 H2O + 18.8 N2 From the equation, 1 kmol fuel + (5 + 18.8)...If you want to get a practiced essay, allege it on our website: OrderCustomPaper.com

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